CBSE Class 10 Maths Notes – Chapter 8 Introduction to Trigonometry
CBSE Class 10 Notes for Mathematics Chapter 8 introduce students to trigonometry—the branch of mathematics dealing with relationships between sides and angles of triangles. These CBSE Class 10 Maths Notes are 100% NCERT aligned and essential for board exam preparation.
1. Introduction to Trigonometry
The word "trigonometry" comes from Greek words tri (three), gon (sides), and metron (measure). In CBSE Class 10 Maths Notes, we focus on right-angled triangles where one angle is exactly 90°.
- Weightage: 4-6 marks in CBSE Board Exam
- NCERT Based: 100% aligned with textbook
- Foundation: Essential for Class 11-12 and competitive exams
- Question Types: MCQs, Short Answer, Long Answer, Case-Study
2. Chapter Overview
CBSE Class 10 Notes for Introduction to Trigonometry cover:
- Trigonometric Ratios – sin θ, cos θ, tan θ, cosec θ, sec θ, cot θ
- Standard Values – For angles 0°, 30°, 45°, 60°, 90°
- Trigonometric Identities – Three fundamental identities
- Complementary Angles – Relationships between (90° – θ) and θ
- Identity Proofs – High-weightage board exam problems
3. Key Concepts (NCERT Aligned)
3.1 Parts of a Right-Angled Triangle
| Term | Definition | Hindi |
|---|---|---|
| Hypotenuse | Longest side opposite to right angle | कर्ण |
| Perpendicular | Side opposite to angle θ | लंब |
| Base | Side adjacent to angle θ | आधार |
3.2 Trigonometric Ratios Class 10
cos θ = BaseHypotenuse = BH
tan θ = PerpendicularBase = PB
sec θ = 1cos θ = HB
cot θ = 1tan θ = BP
- Pandit (Perpendicular) - Har (Hypotenuse) = sin
- Badri (Base) - Har (Hypotenuse) = cos
- Prasad (Perpendicular) - Bole (Base) = tan
3.3 Trigonometric Identities Class 10
Identity 2: 1 + tan²θ = sec²θ
Identity 3: 1 + cot²θ = cosec²θ
4. cos θ × sec θ = 1 5. cos θ = 1sec θ 6. sec θ = 1cos θ
7. tan θ × cot θ = 1 8. tan θ = 1cot θ 9. cot θ = 1tan θ
10. tan θ = sin θcos θ 11. cot θ = cos θsin θ
13. sin²θ = 1 − cos²θ
14. cos²θ = 1 − sin²θ
15. sec²θ − tan²θ = 1
16. tan²θ = sec²θ − 1
17. sec²θ = 1 + tan²θ
18. cosec²θ − cot²θ = 1
19. cot²θ = cosec²θ − 1
20. cosec²θ = 1 + cot²θ
Proof of Identity 1:
Using Pythagoras theorem: P² + B² = H²
Divide by H²: P²H² + B²H² = 1
Therefore: sin²θ + cos²θ = 1 Proved.
3.4 Standard Trigonometric Values Table
| θ | 0° | 30° | 45° | 60° | 90° |
|---|---|---|---|---|---|
| sin θ | 0 | 12 | 1√2 | √32 | 1 |
| cos θ | 1 | √32 | 1√2 | 12 | 0 |
| tan θ | 0 | 1√3 | 1 | √3 | Not defined |
| cosec θ | Not defined | 2 | √2 | 2√3 | 1 |
| sec θ | 1 | 2√3 | √2 | 2 | Not defined |
| cot θ | Not defined | √3 | 1 | 1√3 | 0 |
| Ratios | When θ is increase then value is |
|---|---|
| sin θ, tan θ, sec θ | Increase |
| cos θ, cot θ, cosec θ | Decrease |
| π Radian = 180° | |
3.5 Complementary Angle Relations
Two angles are complementary if their sum equals 90°.
cos(90° − θ) = sin θ sec(90° − θ) = cosec θ
tan(90° − θ) = cot θ cot(90° − θ) = tan θ
4. Important Formulas Box
cos θ = BH sec θ = HB
tan θ = PB cot θ = BP
- sin²θ + cos²θ = 1 – When converting sin to cos or vice versa
- 1 + tan²θ = sec²θ – When tan or sec is involved
- 1 + cot²θ = cosec²θ – When cot or cosec appears
5. Solved Examples (CBSE Pattern)
Question: In ΔABC, right-angled at B, AB = 24 cm, BC = 7 cm. Find sin A and cos A.
Solution:
Using Pythagoras: AC² = AB² + BC² = 24² + 7² = 576 + 49 = 625
AC = 25 cm
For angle A: Perpendicular = BC = 7 cm, Base = AB = 24 cm, Hypotenuse = 25 cm
sin A = 725
cos A = 2425
Question: Evaluate: sin 30° cos 60° + cos 30° sin 60°
Solution:
= (12)(12) + (√32)(√32)
= 14 + 34 = 44 = 1
Question: Prove that: (sin θ + cosec θ)² + (cos θ + sec θ)² = 7 + tan²θ + cot²θ
Solution:
LHS: (sin θ + cosec θ)² + (cos θ + sec θ)²
Expanding: sin²θ + 2 + cosec²θ + cos²θ + 2 + sec²θ
= (sin²θ + cos²θ) + 4 + (1 + cot²θ) + (1 + tan²θ)
= 1 + 4 + 1 + cot²θ + 1 + tan²θ
= 7 + tan²θ + cot²θ = RHS
Hence Proved. ⭐
6. Smart Tricks & Memory Techniques
Hold left hand, palm facing you:
- Little finger (0°): sin = √02 = 0
- Ring finger (30°): sin = √12 = 12
- Middle finger (45°): sin = √22 = 1√2
- Index finger (60°): sin = √32
- Thumb (90°): sin = √42 = 1
Cos values reverse this order!
LHS → Simplify using identities → RHS
- Start from complex side
- Convert everything to sin/cos if stuck
- Look for sin²θ + cos²θ = 1 opportunities
7. Most Important Board Questions
- If sin θ = 35, find cos θ.
- Evaluate: tan 45° + cot 45°
- If sec θ = 54, find tan θ.
- If tan θ = 43, evaluate: 3sin θ + 2cos θ3sin θ − 2cos θ
- Prove that: (cosec θ − cot θ)² = 1 − cos θ1 + cos θ
- Prove that: (1 + cot θ − cosec θ)(1 + tan θ + sec θ) = 2
- Prove that: sec²θ + cosec²θ = sec²θ · cosec²θ
- Prove that: sin θ − 2sin³θ2cos³θ − cos θ = tan θ
8. Common Mistakes to Avoid
- Confusing Base and Perpendicular: Base is adjacent to angle, Perpendicular is opposite
- Wrong Identity: Remember sin²θ + cos²θ = 1 (not 0)
- Undefined Values: tan 90°, sec 90°, cot 0°, cosec 0° are NOT DEFINED
- Sign Errors: sin(90°−θ) = cos θ (not −cos θ)
9. Practice Section
(a) √3 (b) 1√3 (c) √32 (d) 1
10. Frequently Asked Questions
Q: Is Introduction to Trigonometry important for CBSE Class 10 board?
Ans: Yes, it carries 4-6 marks and is essential for advanced mathematics.
Q: How to memorize trigonometric values easily?
Ans: Use the finger trick method and practice the standard values table daily.
Q: Are these CBSE Class 10 Maths Notes based on NCERT?
Ans: Yes, 100% NCERT aligned with CBSE board exam patterns.